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holiday
When a user asks whether today is a public holiday in mainland China → return holiday status/name.
Codex 또는 Claude로 설치 이 Prompt를 복사해 Codex, Claude 또는 다른 어시스턴트에 붙여 넣으면 Skill 페이지를 검토하고 설치를 진행할 수 있습니다.
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When a user asks whether today is a public holiday in mainland China → return holiday status/name.
Codex 또는 Claude로 설치 이 Prompt를 복사해 Codex, Claude 또는 다른 어시스턴트에 붙여 넣으면 Skill 페이지를 검토하고 설치를 진행할 수 있습니다.
SOC 직업 분류 기준
| name | holiday |
| description | When a user asks whether today is a public holiday in mainland China → return holiday status/name. |
GET /api/holiday. If the user asks about another day, explain this API is today-only and do not invent a date parameter for this path.GET /api/holiday.GET /api/holiday already succeeded in this conversation and the user repeats the same question, reuse the last data (still “today” in the same session).GET /api/holiday.{ code, message, data }.data.isHoliday, data.name (or fields as returned).GET /api/holiday — read-only, latest today status per API semantics.
Envelope: HTTP 200 with { code: 0, message: "ok", data: { … } } (standard success shape).
data.isHoliday (boolean) — whether today is treated as a public holiday for this service.data.name (string) — holiday or special-day name; may be empty when there is no named entry (still a valid 200).Trust HTTP status first, then read data for fields above.
name if present and relevant.data verbatim when the API returns localized labels./api/holiday → answer from data.Single GET; no body; follow Steps.
| Status | Agent behavior |
|---|---|
| 200 | Success — use data.isHoliday / data.name even if name is empty. |
| 500 | Server-side error — report briefly; one retry later is acceptable; do not loop. |
| 4xx | Unusual for this GET — if seen, do not blind retry; relay message from JSON if present. |
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