avoid-early-return-in-loops
Use when code uses early return statements inside nested loops to exit upon finding a condition
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Use when code uses early return statements inside nested loops to exit upon finding a condition
用 Codex 或 Claude 帮你安装 复制这段 Prompt,粘贴到 Codex、Claude 或其他助手里,让它检查 Skill 页面并帮你完成安装。
基于 SOC 职业分类
Use when printf statements output strings without trailing newlines
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Use when the program accesses a precomputed table using an offset (e.g., arr[n-1]) that introduces an arithmetic operation between the symbolic input and the index
Use when loop variables iterate over character values (e.g., ASCII codes) to represent different operations or choices
Use when code uses a loop to search for an input value in an array and then uses the found index for further computation
Use when code reads a fixed number of characters into an array and only accesses individual elements
| name | avoid-early-return-in-loops |
| description | Use when code uses early return statements inside nested loops to exit upon finding a condition |
A KLEE-coverage code transformation. Applying it rewrites C source so symbolic execution explores more of the program's behavior.
When code uses early return statements inside nested loops to exit upon finding a condition
Replace early returns with state modification (e.g., setting a flag variable) and check the state after loops complete
Early returns create path termination that prevents KLEE from exploring remaining loop iterations, while state modification allows KLEE to symbolically explore all loop paths and generate more diverse test cases
Before:
#include<stdio.h>
int main(void) { int qq, n, i, u;scanf("%d", &n); for(i = 1;i <= 9;i++) {for(u = 1;u <= 9;u++) { qq = i * u; if(qq == n){puts("Yes"); return 0;}}}puts("No");return 0;}
After:
#include <stdio.h>
int n;
int main() {
scanf("%d", &n);
for (int i = 1; i < 10; i++) {
for (int j = 1; j < 10; j++) {
if (n == i*j)n = 0;
}
}
if (n)printf("No\n");
else printf("Yes\n");
}
818c0968