用 Codex 或 Claude 帮你安装 复制这段 Prompt,粘贴到 Codex、Claude 或其他助手里,让它检查 Skill 页面并帮你完成安装。
直接命令不会经过审查 Prompt;运行前请先检查来源。
npx skills add https://github.com/vibeeval/vibecosystem --skill root-finding命令会保持在同一行。复制前请横向滚动并检查完整内容。
想先保存到本地?可下载 SkillsMP 当前能够提供的文件。
Claude Code CLI commands, flags, headless mode, and automation patterns
OpenAI Codex CLI + Claude Code (Hizir) birlikte kullanim rehberi. Is dagitim pattern'leri, GitHub Actions workflow ornekleri, review dongusu ve iki AI yazilim asistaninin guclu yanlarini birlestiren orchestration stratejileri.
Meta-skill for internal codebase exploration at varying depths (quick/deep/architecture)
基于 SOC 职业分类
正在显示 SKILL.md
| name | root-finding |
| description | Problem-solving strategies for root finding in numerical methods |
| allowed-tools | ["Bash","Read"] |
Use this skill when working on root-finding problems in numerical methods.
Characterize the Problem
Method Selection
| Situation | Method | Implementation |
|---|---|---|
| Bracketed, no derivatives | Bisection, Brent | scipy.optimize.brentq |
| Derivatives available | Newton-Raphson | scipy.optimize.newton |
| No derivatives | Secant method | scipy.optimize.newton (no fprime) |
| System of equations | scipy.optimize.fsolve | Requires Jacobian ideally |
Implement Root Finding
scipy.optimize.brentq(f, a, b) - guaranteed convergence if bracketedscipy.optimize.newton(f, x0, fprime=df) - quadratic convergence near rootscipy.optimize.fsolve(F, x0)Handle Multiple Roots
sympy_compute.py solve "f(x)" --var x for symbolic solutionsVerify Solutions
z3_solve.py prove "f(root) == 0"uv run python -c "from scipy.optimize import brentq; root = brentq(lambda x: x**2 - 2, 0, 2); print('Root:', root)"
uv run python -c "from scipy.optimize import newton; root = newton(lambda x: x**2 - 2, 1.0, fprime=lambda x: 2*x); print('Root:', root)"
uv run python -m runtime.harness scripts/sympy_compute.py solve "x**3 - x - 1" --var x
From indexed textbooks:
See .claude/skills/math-mode/SKILL.md for full tool documentation.