القائمة
Use toSorted() instead of sort() to avoid mutating arrays. Apply when sorting arrays that are React props, state, or otherwise shared/referenced elsewhere.
التثبيت باستخدام Codex أو Claude انسخ هذا Prompt والصقه في Codex أو Claude أو مساعد آخر ليراجع صفحة Skill ويثبّتها لك.
استنادا إلى تصنيف SOC المهني
Create pixelated borders, shadows, and effects for 8-bit retro components. Apply when building 8-bit styled UI components that need authentic pixel art aesthetics.
Create documentation with gaming-specific examples, retro styling, and 8-bit terminology. Apply when documenting gaming blocks, RPG components, or retro-styled UI elements.
Optimize 8-bit animations for smooth performance. Apply when creating animated pixel art, game UI effects, or any retro-styled animations.
Import directly from source files instead of barrel files. Apply when using libraries like lucide-react, @mui/material, or @radix-ui/react-* to reduce bundle size and improve dev boot time.
Use next/dynamic for lazy-loading heavy components. Apply when importing large components like editors, charts, or rich text editors that aren't needed on initial render.
Best practices for wrapping shadcn/ui components. Apply when creating 8-bit styled variants of existing shadcn/ui components.
| name | js-tosorted-immutable |
| description | Use toSorted() instead of sort() to avoid mutating arrays. Apply when sorting arrays that are React props, state, or otherwise shared/referenced elsewhere. |
.sort() mutates the array in place, which can cause bugs with React Use .toSorted() to create a new sorted array without state and props. mutation.
Incorrect (mutates original array):
function UserList({ users }: { users: User[] }) {
// Mutates the users prop array!
const sorted = useMemo(
() => users.sort((a, b) => a.name.localeCompare(b.name)),
[users]
)
return <div>{sorted.map(renderUser)}</div>
}
Correct (creates new array):
function UserList({ users }: { users: User[] }) {
// Creates new sorted array, original unchanged
const sorted = useMemo(
() => users.toSorted((a, b) => a.name.localeCompare(b.name)),
[users]
)
return <div>{sorted.map(renderUser)}</div>
}
Why this matters in React:
Browser support (fallback for older browsers):
.toSorted() is available in all modern browsers (Chrome 110+, Safari 16+, Firefox 115+, Node.js 20+). For older environments, use spread operator:
// Fallback for older browsers
const sorted = [...items].sort((a, b) => a.value - b.value)
Other immutable array methods:
.toSorted() - immutable sort.toReversed() - immutable reverse.toSpliced() - immutable splice.with() - immutable element replacement