用 Codex 或 Claude 帮你安装 复制这段 Prompt,粘贴到 Codex、Claude 或其他助手里,让它检查 Skill 页面并帮你完成安装。
直接命令不会经过审查 Prompt;运行前请先检查来源。
npx skills add https://github.com/KYRIE66nb/codex-omx-public-config --skill pyomo命令会保持在同一行。复制前请横向滚动并检查完整内容。
想先保存到本地?可下载 SkillsMP 当前能够提供的文件。
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| name | pyomo |
| description | Pyomo optimization modeling: LP, MILP, NLP, stochastic programs, solvers, planning. |
| version | 6.7 |
| license | BSD-3-Clause |
Pyomo allows you to define optimization problems using a natural mathematical syntax (Sets, Parameters, Variables, Constraints). It decouples the model from the solver, allowing the same model to be solved by different engines without code changes.
pip install pyomo
# Also install a solver (e.g., GLPK for linear/integer problems)
# Conda: conda install -c conda-forge glpk ipopt
Official docs: http://www.pyomo.org/
GitHub: https://github.com/Pyomo/pyomo
Search patterns: pyo.ConcreteModel, pyo.Constraint, pyo.Objective, pyo.SolverFactory
Pyomo does not have its own solver. It requires external solvers (like glpk for LP/MIP or ipopt for NLP) installed on the system.
pip install pyomo
# Also install a solver (e.g., GLPK for linear/integer problems)
# Conda: conda install -c conda-forge glpk ipopt
import pyomo.environ as pyo
from pyomo.opt import SolverFactory
import pyomo.environ as pyo
# 1. Create Model
model = pyo.ConcreteModel()
# 2. Define Variables
model.x = pyo.Var(within=pyo.NonNegativeReals)
model.y = pyo.Var(within=pyo.NonNegativeReals)
# 3. Define Objective (Minimize x + 2*y)
model.obj = pyo.Objective(expr=model.x + 2*model.y, sense=pyo.minimize)
# 4. Define Constraints
model.con1 = pyo.Constraint(expr=3*model.x + 4*model.y >= 12)
model.con2 = pyo.Constraint(expr=2*model.x + 5*model.y >= 10)
# 5. Solve
solver = pyo.SolverFactory('glpk')
results = solver.solve(model)
# 6. Access Results
print(f"x = {pyo.value(model.x)}, y = {pyo.value(model.y)}")
pyo.value(model.x) to get their numerical result after solving.results.solver.termination_condition.solver.options['tm_limit'] = 60 (or similar depending on the solver) to manage execution time.pyo.log(), pyo.exp(), pyo.sqrt() instead of math.log() or np.log() inside expressions.abs(x) or max(x, y) are non-smooth and can break many solvers. Use reformulations.x + y = 10 are fine, but ensure your units are consistent.import pyomo.environ as pyo
import numpy as np
# ❌ BAD: Using NumPy/Math functions in constraints
# model.con = pyo.Constraint(expr=np.sin(model.x) <= 0.5)
# ✅ GOOD: Use Pyomo-compatible functions
model.con = pyo.Constraint(expr=pyo.sin(model.x) <= 0.5)
# ❌ BAD: Using Python IF for conditional constraints
# if model.x > 10:
# model.con = pyo.Constraint(expr=model.y <= 5)
# ✅ GOOD: Using Big-M notation (for binary variable z)
# y <= 5 + M * (1 - z)
# x >= 10 - M * (1 - z)
# ❌ BAD: Printing a variable directly
# print(model.x) # Returns a reference object, not a number!
# ✅ GOOD: Use value()
print(pyo.value(model.x))
model = pyo.ConcreteModel()
# Data
products = ['A', 'B', 'C']
profit = {'A': 10, 'B': 20, 'C': 15}
limit = 100
# Components
model.P = pyo.Set(initialize=products)
model.x = pyo.Var(model.P, within=pyo.NonNegativeReals)
# Indexed Objective
def obj_rule(model):
return sum(profit[p] * model.x[p] for p in model.P)
model.obj = pyo.Objective(rule=obj_rule, sense=pyo.maximize)
# Indexed Constraint
def limit_rule(model):
return sum(model.x[p] for p in model.P) <= limit
model.con = pyo.Constraint(rule=limit_rule)
# Solving: Minimize (x-2)^2 + (y-2)^2
model = pyo.ConcreteModel()
model.x = pyo.Var(initialize=0) # Initialization is CRUCIAL for NLP
model.y = pyo.Var(initialize=0)
model.obj = pyo.Objective(expr=(model.x - 2)**2 + (model.y - 2)**2)
# Constraint: x^2 + y <= 1
model.con = pyo.Constraint(expr=model.x**2 + model.y <= 1)
# Solve with IPOPT
solver = pyo.SolverFactory('ipopt')
solver.solve(model)
# Binary variable: 1 if we open a warehouse, 0 otherwise
model.use_warehouse = pyo.Var(within=pyo.Binary)
# Integer variable: Number of trucks to buy
model.num_trucks = pyo.Var(within=pyo.NonNegativeIntegers)
# Conditional logic: If warehouse is not used, trucks must be 0
# trucks <= Capacity * use_warehouse
model.cap_con = pyo.Constraint(expr=model.num_trucks <= 100 * model.use_warehouse)
def solve_diet(foods, nutrients, costs, requirements):
model = pyo.ConcreteModel()
model.F = pyo.Set(initialize=foods)
model.N = pyo.Set(initialize=nutrients)
model.x = pyo.Var(model.F, within=pyo.NonNegativeReals)
# Minimize cost
model.obj = pyo.Objective(expr=sum(costs[f] * model.x[f] for f in model.F))
# Meet nutrient requirements
def nutrient_rule(model, n):
return sum(nutrients[f][n] * model.x[f] for f in model.F) >= requirements[n]
model.con = pyo.Constraint(model.N, rule=nutrient_rule)
pyo.SolverFactory('glpk').solve(model)
return {f: pyo.value(model.x[f]) for f in model.F}
# Balancing component fractions in a mixture
# Note: Often becomes non-linear (NLP) if both flow and fraction are variables
def blend_optimization(inputs, target_purity):
model = pyo.ConcreteModel()
# ... model setup ...
# con: sum(flow[i] * purity[i]) / sum(flow[i]) == target_purity
# becomes: sum(flow[i] * purity[i]) == target_purity * sum(flow[i]) (Linearized)
For iterative optimizations, use the previous solution as a starting point.
# For NLP solvers like IPOPT
model.x.set_value(prev_x_value)
solver.solve(model)
Always check why the solver stopped.
from pyomo.opt import TerminationCondition
results = solver.solve(model)
if results.solver.termination_condition == TerminationCondition.optimal:
print("Success")
elif results.solver.termination_condition == TerminationCondition.infeasible:
print("Check your constraints!")
If your NLP model has multiple local minima, IPOPT might get stuck.
# ✅ Solution:
# 1. Provide multiple different initial guesses (multistart).
# 2. Use a global solver like BARON or SCIP.
model.x[model.y] where y is a Var is illegal.
# ✅ Solution: Use model.AddElement or binary variable reformulations.
pyo.value() to extract numerical results from variables after solvingpyo.Set and pyo.Param for organizing data in complex modelspyo.log(), pyo.exp(), etc.) instead of NumPy/math functions in expressionsabs() or max() - use reformulationsPyomo is the ultimate tool for turning high-level mathematical abstractions into solved business and scientific problems. Its ability to bridge the gap between algebraic modeling and high-performance solvers makes it the foundation of modern prescriptive analytics.